A uniform solid cylindrical roller of mass m is being pulled on a horizontal surface with force

• Laws of Motion
• Rotational Motion

A uniform solid cylindrical roller of mass m is being pulled on a horizontal surface with force F parallel to the surface and applied at its centre. If the acceleration of the cylinder is a and it is rolling without slipping then the value of F is:

1. ma
2. 2 ma
3. 3/2 ma
4. 5/3 ma

Solution

Let f be the frictional force.

ma = F – f

mR²/2 * α = fR

mR²/2 * a/R = fR

ma/2 = f

ma = F - ma/2

F = 3ma/2

The correct option is C.