The value of x^2 - 4x + 11 can never be less than

• Quant Quadratic

The value of x2 - 4x + 11 can never be less than

1. 7
2. 8
3. 11
4. 22

Answer

We need to find the minimum value of x² - 4x +11.

The minimum value occurs at -b/2a. here a = 1 and b = -4

-b/2a = -(-4)/(2*1) = 2

Therefore, the expression x² - 4x + 11 is minimum at x = 2.

So, the minimum value is (2² - 4×2 + 11) = 11 - 4 = 7

The correct option is A.