Let ABCDEF be a regular hexagon with each side of length 1 cm
Let ABCDEF be a regular hexagon with each side of length 1 cm. The area (in sq cm) of a square with AC as one side is
- 3√2
- 3
- 4
- √3
Answer
In ∆ABC, AB = 1 cm, BC = 1 cm and ∠B = 120°
Draw perpendicular BO from B to AC. So, in right triangle AOB
cos 30° = AO/AB = AO/1
AO = √3/2
Similarly, OC = √3/2
AC = AO + OC = √3/2 + √3/2 = √3
The square of side √3 cm will have an area of (√3)2 = 3 cm2
The correct option is B.