In a triangle ABC, the lengths of the sides AB and AC equal 17.5 cm and 9 cm respectively
In a triangle ABC, the lengths of the sides AB and AC equal 17.5 cm and 9 cm respectively. Let D be a point on the line segment BC such that AD is perpendicular to BC. If AD = 3 cm, then what is the radius (in cm) of the circle circumscribing the triangle ABC?
- 17.05
- 22.45
- 26.25
- 27.85
Answer
Circumradius, R = abc/4Δ = (AB*AC*BC)/4Δ
Area of triangle, Δ = 1/2 * BC * AD
R = (AB*AC)/2*AD
R = (17.5*9)/(2*3) = 26.25
The correct option is C.