Fourth term of an arithmetic progression is 8. What is the sum of the first 7 terms
Fourth term of an arithmetic progression is 8. What is the sum of the first 7 terms of the arithmetic progression?
- 7
- 35
- 56
- 64
Answer
nth term of Arithmetic Progression = a + (n-1)d
4th term = a + 3d = 8
Sum of first 7 terms = 7/2 (2a + 6d)
2a + 6d = 8 * 2
= 7/2 * 8 * 2 = 56
The correct option is C.