The sum of series, (–100) + (–95) + (–90) + …
The sum of series, (–100) + (–95) + (–90) + …………+ 110 + 115 + 120, is:
- 0
- 220
- 340
- 450
- None of the above
Answer
First Term = -100
Last Term = 120
Number of Terms = 45
Sum = ½n(a + l) = 45(120 - 100)/2 = 450
Another way to solve: negative and positive terms till 100 will cancel each other.
So, sum = 105 + 110 + 115 + 120 = 450
The correct option is D.