In an electrical circuit two resistors of 2 Ω and 4 Ω respectively
In an electrical circuit two resistors of 2 Ω and 4 Ω respectively are connected in series to a 6 V battery. The heat dissipated by the 4 Ω resistor in 5 s will be
- 5 J
- 10 J
- 20 J
- 30 J
Answer
Here, first resistor, R1 = 2 Ω
Second resistor, R2 = 4 Ω
Voltage of cell, V = 6 V
Time taken = t = 5 s
Total resistance of the circuit = R = R1 + R2 = 2 + 4 = 6 Ω
Current, I = V/R = 6/6 = 1 A
Heat dissipated by the 4 Ω resistor in 5 s is given as,
H = I2Rt
H = 1 × 4 × 5 = 20 J
The correct option is C.