The larger of two supplementary angles exceeds the smaller
The larger of two supplementary angles exceeds the smaller by 18°. Find the angles.
Answer
Let larger angle be x°.
∴ Smaller angle = 180° – x°
∴ (x) – (180 – x) = 18
2x = 180 + 18 = 198
⇒ x = 99
∴ The two angles are 99°, 81°.