The larger of two supplementary angles exceeds the smaller

The larger of two supplementary angles exceeds the smaller by 18°. Find the angles.

Answer

Let larger angle be x°.

∴ Smaller angle = 180° – x°

∴ (x) – (180 – x) = 18

2x = 180 + 18 = 198

⇒ x = 99

∴ The two angles are 99°, 81°.