In Figure, PQ and RS are two parallel tangents to a circle with centre O
In Figure, PQ and RS are two parallel tangents to a circle with centre O and another tangent AB with point of contact C intersecting PQ at A and RS at B. Prove that ∠AOB = 90º.
Answer
∆AOD ≅ AOC (SAS)
⇒ ∠1 = ∠2
Similarly, ∠4 = ∠3
⇒ ∠1 + ∠4 = ∠2 + ∠3 = ½(180º)
⇒ ∠2 + ∠3 = 90°
∠AOB = 90°