If the standard deviation of the numbers 2, 3, a and 11 is 3.5
If the standard deviation of the numbers 2, 3, a and 11 is 3.5, then which of the following is true?
- 3a2 – 32a + 84 = 0
- 3a2 – 34a + 91 = 0
- 3a2 – 23a + 44 = 0
- 3a2 – 26a + 55 = 0
Solution
Numbers are 2, 3, a and 11
N = 4
standard Deviation, σ = 3.5
Mean of numbers, μ = (2+3+11+a)/4 = (16+a)/4
\( \sigma^2 = \dfrac{1}{N} \sum (x_i - \mu)^2 \)
3.5 × 3.5 × 4 × 16 = (8+a)2 + (4+a)2 + (16-3a)2 + (a-28)2
= 64 + a2 + 16a + 16 + a2 + 8a + 256 + 9a2 - 96a + a2 + 784 - 56a
= 12a2 - 128a + 1120
196 = 3a2 - 32a + 280
3a2 + 16a + 84 = 0
The correct answer is A.