If the image of the point P(1, –2, 3) in the plane, 2x + 3y – 4z + 22 = 0
If the image of the point P(1, –2, 3) in the plane, 2x + 3y – 4z + 22 = 0 measured parallel to the line, x/1 = y/4 = z/5 is Q, then PQ is equal to:
- 3√5
- 2√42
- √42
- 6√5
Solution
(x - 1)/1 = (y + 2)/4 = (z - 3)/5 = λ
Let midpoint of PQ be M which lines on the plane
M(x, y, z) = (1 + λ, 4λ - 2, 5λ + 3)
2(1 + λ) + 3(4λ - 2) - 4(5λ + 3) + 22 = 0
- 6λ + 6 = 0
λ = 1
M (2, 2, 8), P (1, -2, 3)
PM = √42
PQ = 2√42
The correct option is B.