A stream of electrons from a heated filament was passed between two charged plates
A stream of electrons from a heated filament was passed between two charged plates kept at a potential difference V esu. If e and m are charge and mass of an electron, respectively, then the value of h/λ (where λ is wavelength associated with electron wave) is given by:
- 2meV
- √(meV)
- √(2meV)
- meV
Solution
According to de-broglie, the wavelength associated with a particle of mass m, moving with velocity v is given by the relation
\( \lambda = \dfrac{h}{mv} \)
Kinetic Energy = ½mv2 = eV
m2v2 = 2eVm
mv = √(2eVm)
\( \lambda = \dfrac{h}{\sqrt{2eVm}} \)
The correct option is C.