The ionization energy of hydrogen atom in the ground state is
The ionization energy of hydrogen atom in the ground state is
- 13.6 MeV
- 13.6 eV
- 13.6 Joule
- Zero
Answer
The ionization energy of a hydrogen atom is equal to 13.6 eV because the ground state has an energy of -13.6 eV in a hydrogen atom.
En = - 13.6 eV/n2
For the ground state, n = 1
E = - 13.6 eV
The correct option is B.