The ionization energy of hydrogen atom in the ground state is

The ionization energy of hydrogen atom in the ground state is

  1. 13.6 MeV
  2. 13.6 eV
  3. 13.6 Joule
  4. Zero

Answer

The ionization energy of a hydrogen atom is equal to 13.6 eV because the ground state has an energy of -13.6 eV in a hydrogen atom.

En = - 13.6 eV/n2

For the ground state, n = 1

E = - 13.6 eV

The correct option is B.