If the product of three consecutive positive integers is 15600
If the product of three consecutive positive integers is 15600 then the sum of the squares of these integers is
- 1777
- 1785
- 1875
- 1877
Answer
Given, (n – 1) × (n) × (n + 1) = 15600
As 15600 has 2 zeroes in it, one of n – 1, n or n + 1 should be a multiple of 25.
Dividing 15600 by 25, we get 624, but 624 = 24×26 so, the numbers are 24, 25 and 26
242 + 252 + 262 = 1877
The correct option is D.