A and B together can do a piece of work in 30 days. A having worked for 16 days
A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
- 30 days
- 40 days
- 60 days
- 70 days
Answer
A's one day work = x
B's one day work = y
Let total work be 60 units.
x + y = 2 and 16x + 44y = 60
16x + 16y = 32 and 16x + 44y = 60
28y = 28
y = 1
B's one day work is 1 unit. So, 60 units of work can be completed by B in 60 days.
The correct option is C.